UPDATED

[code]
Given A=B and also @ = "@"
A^2 = AB
A^2 - B^2 = AB - B^2
(A-B)(A+B) = B(A-B)
A + B = B
B + B = B
2B = B

@@ = @

[\code]

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"He was a good little monkey and always very curious..."

[This message has been edited by Paul_Berquam (edited 24 January 2001).]