hmm...
not really...
you should be able to convert:
$_ = $_ + ($>)
to:
$_ =+ ($>)
or:
$_ =+ $>0
without any errors.
sadly that doesn't work as one would hope though...
anyways, there is a stroke in the 22 code that is really obvious.
guess that's the reason why you don't see it.
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KiXnet
