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#149284 - 2005-10-06 02:47 AM Re: KiXgolf: Fragmentation - Public Coding
maciep maciep Korg Regular Registered: 2002-06-14 Posts: 947 Loc: Pittsburgh	Funny, you decided not to keep track but make sure the length was right. I decide that i didn't care what the length was but would just keep track. I heart kix golf.
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#149285 - 2005-10-06 03:01 AM Re: KiXgolf: Fragmentation - Public Coding
maciep maciep Korg Regular Registered: 2002-06-14 Posts: 947 Loc: Pittsburgh	More with Allen's code Code: function f($) dim $h,$c,$o,$t,$a $f=ubound($) for $c=0 to $f for $h=$c+1 to $f $a=$[$c]+$[$h] if len($a)=2*len(join($,""))/($f+1) $o=$o + a +$a+ a+ $[$h]+$[$c] endif next next for each $ in split($o,a) $h=ubound(split($o,$)) if $h>$t $t=$h $f=$ ;endif ;next endfunction Quote: KiXtart Engine KiXtart Version = 4.50 KiXGolf Script = kixgolf_fragmentation.kix Computer OS = Windows XP Professional CPU = Intel(R) Xeon(TM) Speed = 2790 MHz Memory = 1024 MB KiXGolf Scoring Engine Scoring Engine = 3.0.3 KiXGolf Score Tournament = Fragmentation Processing Start = 2005/10/05 20:40:41.411 Processing End = 2005/10/05 20:40:41.661 Duration = 0000/00/00 00:00:00.250 # Tests Run = 180 # Tests Passed = 180 # Tests Failed = 0 Result = passed KiXGolf Score = 221
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#149286 - 2005-10-06 03:07 AM Re: KiXgolf: Fragmentation - Public Coding
Allen Allen KiX Supporter Registered: 2003-04-19 Posts: 4549 Loc: USA	Yeah Baby!
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#149287 - 2005-10-06 03:36 AM

Re: KiXgolf: Fragmentation - Public Coding

Lonkero Offline

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KiX Master Guru

Registered: 2001-06-05
Posts: 22346
Loc: OK

fine.
220:
Code:


function f($)
  dim $h,$c,$o,$t
  $f=ubound($)
  for $c=0 to $f
      for $h=$c+1 to $f
	 $t = a+$[$c]+$[$h]+a
         if len($t)=2+2*len(join($,""))/($f+1)
              $o=$o+$t+$[$h]+$[$c]
         endif
      next
   next
  for each $ in split($o,a)
    $h=ubound(split($o,$))
    if $h>$t
      $t=$h
      $f=$
    ;endif
  ;next
endfunction

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#149288 - 2005-10-06 03:53 AM

Re: KiXgolf: Fragmentation - Public Coding

Lonkero Offline

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KiX Master Guru

Registered: 2001-06-05
Posts: 22346
Loc: OK

Code:


KiXtart Engine
KiXtart Version     = 4.50 (WKIX32.EXE)
KiXGolf Script      = kixgolf_fragmentation.kix

Computer
OS                  = Windows 2000 Professional
CPU                 = Intel Pentium III
Speed               = 797 MHz
Memory              = 376 MB

KiXGolf Scoring Engine
Scoring Engine      = 3.0.3

KiXGolf Score
Tournament          = Fragmentation
Processing Start    = 2005/10/06 04:31:15.674
Processing End      = 2005/10/06 04:31:17.717
Duration            = 0000/00/00 00:00:02.042
Used Processor Time = 00:00:00.981
# Tests Run         = 180
# Tests Passed      = 180
# Tests Failed      = 0
Result              = passed
KiXGolf Score       = 218

Thank you for participating in KiXtart Golf!
Press any key to continue...

Code:


function f($)
  dim $h,$c,$o,$t
  $f=ubound($)
  for $c=0 to $f
      for $h=$c+1 to $f
	 $t = a+$[$c]+$[$h]+aa
         if len($t)=2+2*len(join($))/($f+1)
              $o=$o+$t+$[$h]+$[$c]
         endif
      next
   next
  for each $ in split($o,a)
    $h=ubound(split($o,$))
    if $h>$t
      $t=$h
      $f=$
endfunction

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#149289 - 2005-10-06 03:55 AM

Re: KiXgolf: Fragmentation - Public Coding

Lonkero Offline

Offline

KiX Master Guru

Registered: 2001-06-05
Posts: 22346
Loc: OK

217
Code:


function f($)
  dim $h,$c,$o,$t
  $f=ubound($)
  for $c=0 to $f
      for $h=$c+1 to $f
	 $t = a+$[$c]+$[$h]+a
         if len($t)=1+2*len(join($))/($f+1)
              $o=$o+$t+$[$h]+$[$c]
         endif
      next
   next
  for each $ in split($o,a)
    $h=ubound(split($o,$))
    if $h>$t
      $t=$h
      $f=$
endfunction

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#149290 - 2005-10-06 03:57 AM

Re: KiXgolf: Fragmentation - Public Coding

Lonkero Offline

Offline

KiX Master Guru

Registered: 2001-06-05
Posts: 22346
Loc: OK

Code:



KiXtart Engine
KiXtart Version     = 4.50 (WKIX32.EXE)
KiXGolf Script      = kixgolf_fragmentation.kix
 
Computer
OS                  = Windows 2000 Professional
CPU                 = Intel Pentium III
Speed               = 797 MHz
Memory              = 376 MB
 
KiXGolf Scoring Engine
Scoring Engine      = 3.0.3
 
KiXGolf Score
Tournament          = Fragmentation
Processing Start    = 2005/10/06 04:35:57.640
Processing End      = 2005/10/06 04:36:01.415
Duration            = 0000/00/00 00:00:03.775
Used Processor Time = 00:00:01.111
# Tests Run         = 180
# Tests Passed      = 180
# Tests Failed      = 0
Result              = passed
KiXGolf Score       = 215
 
Thank you for participating in KiXtart Golf!

Code:

 function f($)
  dim $h,$c,$o,$t
  $f=ubound($)
  for $c=0 to $f
      for $h=$c+1 to $f
	 $t = a+$[$c]+$[$h]
         if len($t)=2*len(join($))/($f+1)
              $o=$o+$t+a+$[$h]+$[$c]
         endif
      next
   next
  for each $ in split($o,a)
    $h=ubound(split($o,$))
    if $h>$t
      $t=$h
      $f=$
endfunction

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#149291 - 2005-10-06 04:05 AM Re: KiXgolf: Fragmentation - Public Coding
Allen Allen KiX Supporter Registered: 2003-04-19 Posts: 4549 Loc: USA	Geezus... That's amazing!
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#149292 - 2005-10-06 06:08 AM Re: KiXgolf: Fragmentation - Public Coding
maciep maciep Korg Regular Registered: 2002-06-14 Posts: 947 Loc: Pittsburgh	Here's another apporach using rnd() that just came to me. Golf away.... Code: Function f($) dim $u,$i,$j $u=ubound($) while 1 dim $x[$u],$c $f='' for $j=1 to 2*len(join($,""))/($u+1) $f=$f+rnd(1) next for $j=0 to $u for $i=0 to $u if 0=($i=$j)+ $x[$i] + $x[$j]+ ($[$j]+$[$i]<>$f) $c=$c+2 $x[$i]=1 $x[$j]=1 if $c>$u exit ;endif ;endif ;next ;next ;loop endfunction Quote: KiXtart Engine KiXtart Version = 4.50 KiXGolf Script = kixgolf_fragmentation.kix Computer OS = Windows XP Professional CPU = Intel(R) Xeon(TM) CPU 2.80GHz Speed = 2790 MHz Memory = 1024 MB KiXGolf Scoring Engine Scoring Engine = 3.0.3 KiXGolf Score Tournament = Fragmentation Processing Start = 2005/10/05 23:46:34.779 Processing End = 2005/10/05 23:47:04.670 Duration = 0000/00/00 00:00:29.891 # Tests Run = 180 # Tests Passed = 180 # Tests Failed = 0 Result = passed KiXGolf Score = 217
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#149293 - 2005-10-06 06:22 AM Re: KiXgolf: Fragmentation - Public Coding
Sealeopard Sealeopard KiX Master Registered: 2001-04-25 Posts: 11164 Loc: Boston, MA, USA	Seems you guys are having fun. I apologize for not having opened the public round. I sent an email to Jooel asking him to open the public round (Shawn should have a copy), which bounced because I had his old email address. My fault. To make a long story short, I was stuck at work in a meeting that went way into the evening, thus sneaked out to send an email via Blackberry :-( I should be able to provide the private coding winners tomorrow and then we'll see how the public round goes. Interesting that the tricks from the last round are now being adapted and pushed to even more extremes. wonder what Ruud would say about this _________________________ There are two types of vessels, submarines and targets.
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#149294 - 2005-10-06 02:02 PM Re: KiXgolf: Fragmentation - Public Coding
maciep maciep Korg Regular Registered: 2002-06-14 Posts: 947 Loc: Pittsburgh	By the way, it looks like Allen's code is flawed like my original was. It passes all of the tests, but, for example, if you change test 54 to '0,00,10,1', it breaks. It returns 000 instead of 100. It depends on the order of when combinations are added to $o
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#149295 - 2005-10-06 02:50 PM Re: KiXgolf: Fragmentation - Public Coding
Lonkero Lonkero KiX Master Guru Registered: 2001-06-05 Posts: 22346 Loc: OK	you saying that all of the codes by allen are flawed? hmm... that makes me a leader again with your code Jens, nice to hear you didn't forget us. and no worries, we did manage on our own too. _________________________ ! download KiXnet
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#149296 - 2005-10-06 02:58 PM Re: KiXgolf: Fragmentation - Public Coding
maciep maciep Korg Regular Registered: 2002-06-14 Posts: 947 Loc: Pittsburgh	actually, i think i'm the leader with the new code i posted...or maybe i missed something. And here is the code that 'found' Allen's flaw. Logically, it should work the same as his original, but it fails. Code: function f($) dim $h,$c,$o,$t $f=ubound($) for $c=0 to $f for $h=0 to $f $t = a+$[$c]+$[$h] if len($t)=2*len(join($))/($f+1) and $h<>$c $o=$o+$t endif next next for each $ in split($o,a) $h=ubound(split($o,$)) if $h>$t $t=$h $f=$ endfunction
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#149297 - 2005-10-06 03:39 PM Re: KiXgolf: Fragmentation - Public Coding
Lonkero Lonkero KiX Master Guru Registered: 2001-06-05 Posts: 22346 Loc: OK	you saying this fails or the original? what is the test of yours? I will add it to my tests and get it over with... _________________________ ! download KiXnet
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#149298 - 2005-10-06 03:45 PM Re: KiXgolf: Fragmentation - Public Coding
Allen Allen KiX Supporter Registered: 2003-04-19 Posts: 4549 Loc: USA	Possible solutions: 000 000 010 100 001 100 101 110 Which you are correct 000 would show up first. But in this case how would you know which is right since they both are just as likely to be the correct answer, and there are no duplicates?
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#149299 - 2005-10-06 03:48 PM Re: KiXgolf: Fragmentation - Public Coding
Lonkero Lonkero KiX Master Guru Registered: 2001-06-05 Posts: 22346 Loc: OK	the introduction said, there is no possible duplicates. that is, each test has only 1 match. if this line works with 2, then it's not cool. if only one, it can be calculated. _________________________ ! download KiXnet
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#149300 - 2005-10-06 03:51 PM Re: KiXgolf: Fragmentation - Public Coding
Allen Allen KiX Supporter Registered: 2003-04-19 Posts: 4549 Loc: USA	So that means the that test is invalid, right?
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#149301 - 2005-10-06 03:54 PM Re: KiXgolf: Fragmentation - Public Coding
Allen Allen KiX Supporter Registered: 2003-04-19 Posts: 4549 Loc: USA	By duplicates, I meant from the input array.
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#149302 - 2005-10-06 03:58 PM Re: KiXgolf: Fragmentation - Public Coding
maciep maciep Korg Regular Registered: 2002-06-14 Posts: 947 Loc: Pittsburgh	The test case is valid. you cannot 0 to 00 and then add 00 to 0 and consider those as different combinations. Yeah, you have two, but they're the same so it's really one. Allen's code sees them as two diff combinations though.
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#149303 - 2005-10-06 04:02 PM Re: KiXgolf: Fragmentation - Public Coding
Allen Allen KiX Supporter Registered: 2003-04-19 Posts: 4549 Loc: USA	ah that sucks... ... So now I need to figure out why it passed test two when I change the order around.
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