Nope, both wrong; both solutions give:
'AA AA', 'A' ==> CC DD
'AA AA. AA AA', 'A' ==> CC DD. DD EE
The code could be 387 and be correct if
Code:
$o=IIf(0<InSTR('! ? . ',SubSTR($t,$j,2)),-1,$o+($=' '))
this gives
'AA AA', 'A' ==> CC DD
'AA AA. AA AA', 'A' ==> CC DD. CC DD
Which in my opinion is correct.
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Greetz,
Patrick Rutten
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